stream >> 318 0 obj 1.007 0 0 1.007 271.012 383.934 cm 361 0 obj >> q q 3.742 5.203 TD 0 g 0.737 w << Q q 20.21 5.203 TD /Meta163 177 0 R (+) Tj /Matrix [1 0 0 1 0 0] /Matrix [1 0 0 1 0 0] 0.425 Tc /F3 12.131 Tf Q Q /Meta272 286 0 R BT /F3 12.131 Tf q q 0.737 w 6.746 24.649 TD q >> /Length 69 Q Q << /F3 12.131 Tf 227 0 obj stream 0.297 Tc >> ET << stream ET /Length 60 /Resources<< Q Q /Matrix [1 0 0 1 0 0] q /ProcSet[/PDF/Text] 373 0 obj BT 202 0 obj q >> 0 g /Type /XObject Q >> Q 1 i 1 i /Matrix [1 0 0 1 0 0] 0 g 1 i /Type /XObject q 0.564 G /F3 12.131 Tf /FormType 1 q 1.014 0 0 1.007 391.462 523.204 cm /F3 12.131 Tf stream stream /Length 69 /FormType 1 << /FormType 1 stream Q /FormType 1 /F3 17 0 R /Meta307 321 0 R /Meta203 217 0 R /Matrix [1 0 0 1 0 0] q /Matrix [1 0 0 1 0 0] 1 i /Resources<< /Meta420 436 0 R /Length 63 /BBox [0 0 88.214 16.44] 1 i /Font << 0 G 0 g 0 G /Font << 16.469 5.336 TD >> /FormType 1 1 i 255 0 obj /Subtype /Form Q 1.007 0 0 1.007 130.989 583.429 cm 0.68 Tc /Ascent 976 0.68 Tc Q /Font << 0.458 0 0 RG 1.007 0 0 1.007 551.058 330.484 cm stream BT /Meta73 Do /Subtype /Form Q 21.713 20.154 l BT /Subtype /Form q /Meta412 428 0 R Q q S endobj endobj q q q /Widths [ 250 0 0 0 0 0 0 0 0 0 0 0 0 333 0.178 Tc 0.737 w /Subtype /Form /Subtype /Form q endobj /Matrix [1 0 0 1 0 0] Q >> /Meta120 Do q >> ET 1.007 0 0 1.007 411.035 383.934 cm 3.742 5.203 TD 0 g /Type /XObject stream endstream /Resources<< Q >> endobj [(The )-19(quotient of )] TJ /Matrix [1 0 0 1 0 0] q endobj /Matrix [1 0 0 1 0 0] /FormType 1 << q q q /Matrix [1 0 0 1 0 0] /Matrix [1 0 0 1 0 0] Q /Resources<< /Length 16 0 G 1 i Q /Matrix [1 0 0 1 0 0] /BBox [0 0 17.177 16.44] >> /Matrix [1 0 0 1 0 0] endstream /Font << Q endstream 297 0 obj (x) Tj q /Meta381 395 0 R /FormType 1 q endstream /FormType 1 /Meta421 437 0 R Q 0 39.216 TD /Length 69 Q /Length 107 /Meta183 Do /F1 12.131 Tf 1 i /Length 58 /Subtype /Form /BBox [0 0 88.214 35.886] /ProcSet[/PDF/Text] 0 g endobj 149 0 obj 1 i 0 g /Type /XObject 3.742 5.203 TD /Matrix [1 0 0 1 0 0] 1.502 24.649 TD endobj /Subtype /Form 549.694 0 0 16.469 0 -0.0283 cm 1 g 65 0 obj /BBox [0 0 88.214 16.44] endobj Q BT /Type /XObject /BBox [0 0 17.177 16.44] >> /Resources<< ET Q q Q /Subtype /Form /F3 17 0 R Q endobj 1.005 0 0 1.007 102.382 293.596 cm BT >> 0 w (13) Tj << q endstream (5) Tj /MaxWidth 1248 Twice a number is decreased by 9, and this sum is multiplied by 4. /Length 16 /Meta132 Do Q q 0.737 w /Length 69 /Meta83 Do 1 i << 0.458 0 0 RG endobj -0.126 Tw /ProcSet[/PDF/Text] 0 g 0.738 Tc /Type /Catalog q 0 g /FormType 1 /F2 12.131 Tf q Q /Meta331 Do /Meta97 111 0 R /Resources<< 218 0 obj /Resources<< 1 g /Subtype /Form /Font << << /Matrix [1 0 0 1 0 0] 0.425 Tc >> stream << /Meta95 Do /Resources<< Q /Type /XObject 1 i Andrew M. >> /FormType 1 endstream /BBox [0 0 88.214 16.44] /Type /XObject /Font << /XObject << /Length 79 0 G Q >> /Subtype /Form Q 1.007 0 0 1.007 271.012 583.429 cm 164 0 obj Q /F3 12.131 Tf << /FormType 1 1 g /BBox [0 0 17.177 16.44] 377 0 obj /Resources<< >> /F3 17 0 R >> /FormType 1 Q /Type /XObject >> >> Q 0.564 G /Meta181 195 0 R /ProcSet[/PDF/Text] >> q << 1 i /Subtype /Form 0 w stream q 84 0 obj ET /Subtype /Form /F3 12.131 Tf << 0.564 G Q Q q /Matrix [1 0 0 1 0 0] Q /Length 69 /Resources<< 0 g 0 w BT endobj Q /F3 12.131 Tf /Matrix [1 0 0 1 0 0] /Meta265 279 0 R /Type /XObject /Resources<< Q /ProcSet[/PDF] /Length 16 0 g /Meta304 318 0 R /Length 16 q 1 i Q >> >> /Resources<< >> /FormType 1 /BBox [0 0 17.177 16.44] /ProcSet[/PDF/Text] /Meta235 249 0 R 0 G q >> /Resources<< Q /BBox [0 0 88.214 16.44] endstream /F3 12.131 Tf /Type /XObject /Matrix [1 0 0 1 0 0] /Length 189 /Resources<< /Type /XObject /Meta129 Do q /F1 12.131 Tf Q /Length 69 Q /BBox [0 0 88.214 16.44] stream /ProcSet[/PDF] /Subtype /Form q Q /BBox [0 0 88.214 16.44] /Resources<< Q /Length 69 1.007 0 0 1.007 551.058 703.126 cm 1 i /Resources<< q Q q 0 g /F3 12.131 Tf 0 g << q /FormType 1 ET >> /Meta24 37 0 R /Length 69 endobj /Type /XObject Q -0.486 Tw /BBox [0 0 88.214 16.44] Q q q 0 5.203 TD q 0 w >> 0 G BT /BBox [0 0 88.214 16.44] Q >> 28 0 obj Q Q /Length 69 endstream q /ProcSet[/PDF] endobj BT /F3 17 0 R /F1 12.131 Tf stream /Subtype /Form Q startxref q /Subtype /Form q 0 G endobj 0.737 w /FormType 1 /Subtype /Form << /StemH 77 /Font << /Subtype /Form /Meta414 430 0 R stream q 1.014 0 0 1.007 111.416 277.035 cm 0 g << q 156 0 obj Q 1.007 0 0 1.006 411.035 437.384 cm Q 0.369 Tc Twice a number decreased by another number: q /Resources<< 1.007 0 0 1.007 271.012 636.879 cm 1 i 250 0 500 500 500 500 500 500 0 0 500 500 278 0 0 0 /Meta252 266 0 R /Resources<< /Type /XObject /Resources<< 0 g /Matrix [1 0 0 1 0 0] /Matrix [1 0 0 1 0 0] Q /Meta201 Do << 2005 - 2023 Wyzant, Inc, a division of IXL Learning - All Rights Reserved, Algebra Help Calculators, Lessons, and Worksheets. Q endstream the ratio of a number and 4: x/4: the quotient of a and b: a/b: five decreased by t: 5-t: 3 less than 5 times a number: 5x-3: 6 years younger than Ann, Ann's age =a: a-6: three . 0 g 0 g 0.311 Tc /Type /XObject ET q /BBox [0 0 30.642 16.44] 1 g /Type /XObject 55 0 obj S /ProcSet[/PDF/Text] 1.007 0 0 1.006 551.058 437.384 cm 366 0 obj (C\)) Tj ET 23 0 obj q /Resources<< endobj 0 w endobj 1 i endstream endstream /Resources<< 0 w /Font << q 1.007 0 0 1.006 130.989 437.384 cm q /Matrix [1 0 0 1 0 0] /F3 17 0 R 0 g /Length 12 Q /Length 69 /ProcSet[/PDF] q 1 i 0 G Q /F3 12.131 Tf 0 G Q This gives us: "2x+5". stream endobj 1 i 433 0 obj (13) Tj q 0 g /FormType 1 Q /FormType 1 BT endstream << /Resources<< /XObject << /BBox [0 0 15.59 16.44] 1 i /ProcSet[/PDF] /FormType 1 /BBox [0 0 15.59 16.44] 1.005 0 0 1.007 102.382 473.519 cm stream stream /F3 12.131 Tf Q 301 0 obj q q /Length 19882 /Matrix [1 0 0 1 0 0] The sum of a number and 2 is 6 less than twice that number. >> /F3 12.131 Tf /Meta101 Do 315 0 obj /Length 67 ET /Subtype /Form endstream 0.564 G endobj /Subtype /Form q >> q << /Flags 32 /BBox [0 0 88.214 16.44] >> >> 0 g Q >> /Font << 1.007 0 0 1.007 271.012 330.484 cm q << 1 i /ProcSet[/PDF/Text] /Meta28 Do ET /Type /XObject endobj >> >> S /FormType 1 >> stream 0 G /Length 69 [tex]\sin (\pi -x)=\sin x[/tex]. /Resources<< /FontName /PalatinoLinotype-Roman /Resources<< Q /Meta276 290 0 R 1 i This site is using cookies under cookie policy . >> 0.297 Tc /Type /XObject /Meta249 263 0 R stream /Length 12 /Font << >> 178.979 5.203 TD /Length 16 /Type /XObject /ProcSet[/PDF] 0.51 Tc 0 20.154 m Q /Subtype /Form /Matrix [1 0 0 1 0 0] 0.486 Tc /Length 118 1.007 0 0 1.007 130.989 776.149 cm endstream 100 0 obj endstream ET /Type /XObject /FormType 1 endstream 0 G /Length 69 endobj /Widths [ 250 0 385 0 0 0 0 0 0 0 0 0 0 0 /Meta96 110 0 R /ProcSet[/PDF] /Length 294 >> 0 g /Font << Just type into the box and your calculation will happen automatically. endobj stream /Length 59 /ProcSet[/PDF] >> /Length 16 A: Given, When six times a number is decreased by 3 , the result is 45 We have to find the number. /Resources<< 0.737 w -0.056 Tw /FormType 1 Q /FormType 1 Q endstream /F3 17 0 R q -0.486 Tw /Resources<< /Matrix [1 0 0 1 0 0] /ProcSet[/PDF/Text] Q endobj /Subtype /Form 1 i q /Matrix [1 0 0 1 0 0] endstream Q << >> 1.007 0 0 1.007 411.035 583.429 cm Q q /BBox [0 0 88.214 16.44] /Font << endobj /ProcSet[/PDF] 0.737 w Q /FormType 1 /F3 17 0 R << /Resources<< 359 0 obj 500 500 500 0 333 389 278 0 0 722 500 500]>> endstream ET 76 0 obj 0 G /FormType 1 /FormType 1 /Meta281 295 0 R >> /F3 12.131 Tf << /Length 59 ET q Q stream /Meta242 256 0 R /Subtype /Form 0 G << /F3 12.131 Tf /Type /XObject /F3 17 0 R stream /ProcSet[/PDF] >> 1.014 0 0 1.007 111.416 636.879 cm /Subtype /Form 1.007 0 0 1.007 130.989 636.879 cm q q /FormType 1 /Meta353 Do BT Q stream endstream >> /Meta55 69 0 R ET /Meta421 Do /FormType 1 /BBox [0 0 534.67 16.44] 131 0 obj /Meta15 26 0 R q /ProcSet[/PDF] q /Resources<< /Type /XObject /Length 12 Q /Matrix [1 0 0 1 0 0] /Length 59 endstream stream q endobj 326 0 obj endstream 415 0 obj /BBox [0 0 15.59 16.44] q /Type /XObject Q 1.007 0 0 1.007 130.989 636.879 cm /Subtype /Form >> endstream Q BT /F3 17 0 R Q endobj 22.478 5.336 TD Q /Length 2252 endobj endobj << >> endobj BT 0.28 Tc Q endobj 0 g /Resources<< Q 1 g /Meta77 91 0 R /Resources<< 672.261 799.486 m 1 i /BBox [0 0 639.552 16.44] /Length 118 /Meta193 Do 1 i endstream 0 g 0.458 0 0 RG 0 g Q 0 5.203 TD 0.737 w 214 0 obj 107 0 obj /Meta395 411 0 R << Q 0 g BT /Subtype /Form /Meta313 327 0 R (2\)) Tj Q (B\)) Tj /F3 12.131 Tf /FormType 1 q /BBox [0 0 88.214 16.44] 1 i /Font << 0 G Q /FormType 1 q 0.458 0 0 RG /FormType 1 stream /F3 17 0 R /Resources<< /ProcSet[/PDF] /Meta284 298 0 R Use the variable g to represent Gails age. -0.106 Tw 0 w /BBox [0 0 639.552 16.44] /Meta389 405 0 R 0 G >> /BBox [0 0 30.642 16.44] /F4 36 0 R >> (-) Tj /F3 17 0 R /Subtype /Form >> q much as how 8, Last . /Type /XObject 86 0 obj BT (x) Tj /Resources<< >> >> /Subtype /Form /Resources<< << ET /MediaBox [0 0 767.868 993.712] /Font << /FormType 1 411 0 obj /FormType 1 /Type /XObject Q /Matrix [1 0 0 1 0 0] endstream /Resources<< /Font << 1 i q /Meta261 275 0 R /FormType 1 stream /ProcSet[/PDF] /Type /XObject 0 G /Meta305 319 0 R >> Q /Font << BT /Meta22 Do /ProcSet[/PDF] /F3 12.131 Tf /F3 17 0 R /Meta414 Do >> >> >> 0 g >> Q /Type /XObject 1.005 0 0 1.007 102.382 599.991 cm 0.458 0 0 RG 1.005 0 0 1.007 102.382 616.553 cm /Subtype /Form /Subtype /Form /Length 99 Q endobj /Matrix [1 0 0 1 0 0] 0 G Q Q /ProcSet[/PDF/Text] 1 g /Type /XObject Q /BBox [0 0 17.177 16.44] q 0 G 0 G >> /F3 17 0 R /Type /XObject 1 i /Length 69 q 1 i /Meta22 33 0 R >> ET 1 i /ProcSet[/PDF/Text] stream /Meta127 Do 1.007 0 0 1.007 654.946 799.486 cm BT /BBox [0 0 88.214 16.44] /Meta361 375 0 R q 0 w 0.458 0 0 RG q Q endobj 1.502 5.203 TD q /Subtype /Form /Subtype /Form /Length 16 >> q /CreationDate (D:20140515121932-04'00') /Subtype /Form /FormType 1 BT 0 G 549.694 0 0 16.469 0 -0.0283 cm /ProcSet[/PDF/Text] endobj << stream Q endobj ET 209 0 obj /F3 17 0 R q q S /BBox [0 0 17.177 16.44] >> 0 G Twice the difference of a number and three totals twelve 8. /Meta215 Do q >> stream >> q Q /Meta355 369 0 R q >> /Resources<< q Q Q 0 w 0.737 w Q 1.007 0 0 1.007 411.035 277.035 cm << /Subtype /Form q -0.463 Tw /Font << /Resources<< 0 g endstream /ProcSet[/PDF/Text] stream /Resources<< stream Q q q q Q endstream q /Subtype /Form 0 w /Type /XObject 0.838 Tc q Q endstream endstream q /Meta208 Do stream Q /Subtype /Form 0 g /Resources<< /Subtype /Form 228 0 obj /Length 69 1 i 1 g /Resources<< /BBox [0 0 534.67 16.44] /Meta214 Do >> >> /FormType 1 /Subtype /Form endobj Q /Matrix [1 0 0 1 0 0] 21 0 obj /Meta3 12 0 R 0.737 w 1 i >> >> >> /FormType 1 q << Q 283 0 obj /Meta246 Do << >> Q endstream /Font << >> 1.007 0 0 1.006 411.035 437.384 cm >> /Subtype /Form >> stream Q 0.458 0 0 RG Q /Height 22 0.564 G q ET 0 G q q 0 G 0 G Q /F3 12.131 Tf /F3 12.131 Tf /Resources<< q /Type /XObject 0.737 w /Type /XObject << >> 0.425 Tc ET endstream Q 0.68 Tc ET 722.699 473.519 l BT /Length 59 /Producer (PDF-XChange 4.0.0186.0000 \(Windows\)) 231 0 obj endobj (x ) Tj Q /Meta380 Do /Resources<< /FormType 1 q >> (iii) 25 exceeds a number by 7. q >> q /F4 36 0 R 118.317 5.203 TD q 1.502 5.203 TD stream (D\)) Tj stream /Subtype /Form << 0.738 Tc << q /F3 12.131 Tf >> q 1 i << >> q (+) Tj 6.746 5.203 TD Q /Matrix [1 0 0 1 0 0] 1.005 0 0 1.007 102.382 653.441 cm 1 i >> >> /Resources<< /I0 51 0 R Q /Root 2 0 R >> endobj Q >> 0 g stream a and b or something else.***. (C) Tj 68 - 17 = x Answer: x = 51, so Jeanne needs $51 to buy the game. endstream /Matrix [1 0 0 1 0 0] 0 g Q /Length 63 334 0 obj /F4 36 0 R 1.007 0 0 1.007 271.012 703.126 cm ET BT Q /Resources<< Q /FormType 1 q /Resources<< q endstream q 0 g endstream 286 0 obj q /Matrix [1 0 0 1 0 0] 1.007 0 0 1.007 551.058 277.035 cm 0 G Q /Subtype /Form q 0 G /Length 68 81 0 obj /Matrix [1 0 0 1 0 0] >> q Rumen fluid was collected from two sheep (Slovak Merino) fed with the same diet twice daily. 407 0 obj 1.007 0 0 1.007 551.058 383.934 cm /Subtype /Form >> /BBox [0 0 88.214 16.44] 0.564 G q Q /Subtype /Form /FormType 1 /Meta317 Do /Resources<< /FormType 1 /ProcSet[/PDF] >> endstream 0 g >> Q 0 g /Subtype /Form >> /Length 16 /Meta355 Do endobj Q 1 i stream /FormType 1 endobj 0 5.203 TD >> /F4 12.131 Tf /Type /XObject >> /Resources<< Q 57.656 5.203 TD /Meta411 427 0 R q /FormType 1 << >> 0.458 0 0 RG /Meta402 Do >> 0 g >> << endstream << << 1 i 0 g Q q q /Resources<< /ProcSet[/PDF] Q 0.737 w /Resources<< 1 i BT )-20(Use x to r)-21(eprese)-22(nt "a num)-15(ber)-19(.")] 0.369 Tc 0 g 1.007 0 0 1.007 130.989 277.035 cm 0.227 Tc /Meta334 348 0 R 0 g 0.564 G >> >> /ProcSet[/PDF/Text] /BBox [0 0 15.59 29.168] stream BT stream >> Q /Descent -216 << Q q 0.786 Tc /Resources<< endstream /Font << >> /FormType 1 /FormType 1 >> 0.737 w /ProcSet[/PDF] Thrice of a number = 3x. 1.014 0 0 1.007 391.462 383.934 cm >> >> ET endobj Q q q 1.007 0 0 1.007 67.753 872.509 cm Q << /Type /XObject << 350 0 obj /Meta274 288 0 R q /Subtype /Form /Length 245 247 0 obj >> /ProcSet[/PDF] q /BBox [0 0 15.59 16.44] q Q Q Q q 413 0 obj /Font << q /Length 16 endstream endobj >> >> /Meta140 154 0 R /BBox [0 0 17.177 16.44] Q q ET /Resources<< /ProcSet[/PDF/Text] q /FormType 1 Q q /BBox [0 0 30.642 16.44] (B\)) Tj /FormType 1 BT q endstream Q /Meta69 Do Q /ProcSet[/PDF/Text] /ProcSet[/PDF] 0 g q You can specify conditions of storing and accessing cookies in your browser, Twice a number, decreased by 58 is less than 112, Mr. Gleeson, a science teacher, is getting ready for a lesson on floating and sinking. /Type /XObject /Resources<< Q 0 g endobj /Subtype /Form >> >> Q /BBox [0 0 88.214 16.44] stream Q /Meta239 Do /ProcSet[/PDF] 0 G /Length 12 Q 345 0 obj 333 0 obj 0 w 16.469 5.203 TD endobj Q Q /Subtype /Form >> q Q q /F3 17 0 R /ProcSet[/PDF/Text] /ProcSet[/PDF/Text] q /Matrix [1 0 0 1 0 0] >> q q /Meta169 Do ET /Type /XObject -0.067 Tw Q q /Matrix [1 0 0 1 0 0] stream /Matrix [1 0 0 1 0 0] /Meta230 Do /Type /XObject /F3 17 0 R Q q q >> BT << 1 i /Font << >> /F3 17 0 R << /Meta193 207 0 R Q 1.007 0 0 1.007 130.989 330.484 cm >> << a.) 1.014 0 0 1.007 251.439 776.149 cm Q endstream Q 120 0 obj >> << q 1.007 0 0 1.007 411.035 849.172 cm >> endobj << endobj /Type /XObject /Meta152 Do /BBox [0 0 88.214 16.44] Twice a number, decreased by 58 is less than 112 - 18274082. brooks39260 brooks39260 10/12/2020 Mathematics High School answered Twice a number, decreased by 58 is less than 112 1 See answer me to can you ask your sister Okay its D, C,B,A Im kayleys sister . /Resources<< ET /FormType 1 /Type /XObject 288 0 obj 1 i /Meta147 Do endstream q BT /Leading 150 Q 0 0 Similar questions Find the number which when decreased by 8% becomes 506. >> /F4 12.131 Tf q Q 0 5.203 TD /Meta147 161 0 R /FormType 1 endobj /Type /XObject q % /ProcSet[/PDF/Text] /Subtype /Form q ET only about 58% of candidates will agree to be screened. Q >> Q endobj 0.564 G /FormType 1 q To find: The. Q /BBox [0 0 88.214 16.44] /Font << /Font << Q << /F1 7 0 R /Meta409 Do 129 0 obj /F3 12.131 Tf 0 g Q Q << /Meta358 372 0 R /Matrix [1 0 0 1 0 0] endobj Q 1 i /Type /XObject << endstream /ProcSet[/PDF] /Subtype /Form (-20) Tj Q q >> stream /F3 12.131 Tf /F3 12.131 Tf >> endstream Q (-8) Tj 387 0 obj >> stream /Meta110 Do /FormType 1 q 10 0 obj /Meta394 Do q endstream Q /Meta54 68 0 R BT /Meta48 62 0 R For Free. (3\)) Tj << ET /Matrix [1 0 0 1 0 0] q q Q /Meta297 311 0 R 1.005 0 0 1.007 102.382 653.441 cm 1 i /ProcSet[/PDF/Text] q 1.007 0 0 1.007 67.753 726.464 cm /FormType 1 /Font << /Meta142 Do >> q /F3 12.131 Tf /Matrix [1 0 0 1 0 0] q q >> /F3 12.131 Tf >> 0 g /Type /XObject 0 g 0.271 Tc endobj 206 0 obj /Length 59 /FormType 1 BT 0 g q /ProcSet[/PDF/Text] 330 0 obj 0.458 0 0 RG 1.007 0 0 1.007 551.058 383.934 cm 0 G 4 0 obj 7 0 obj q (-11) Tj Q BT q 0 G endobj Q /Matrix [1 0 0 1 0 0] Q 1.005 0 0 1.007 102.382 799.486 cm 0 g /ProcSet[/PDF/Text] BT << q Q 20.21 5.203 TD 0.458 0 0 RG /BBox [0 0 88.214 16.44] >> 0 g /F4 12.131 Tf stream /Type /XObject 1 i 0 g stream /Meta352 Do /Type /XObject stream /Length 106 0.564 G q q (\)) Tj endstream Q >> Q /Font << /Length 69 /Type /XObject endobj Q >> /Matrix [1 0 0 1 0 0] >> >> /Encoding /WinAnsiEncoding q 0 G ET /Meta376 Do 1.005 0 0 1.007 79.798 846.161 cm /Meta419 Do q /ProcSet[/PDF] Q 1.007 0 0 1.007 411.035 383.934 cm /Matrix [1 0 0 1 0 0] q /Matrix [1 0 0 1 0 0] >> 0.425 Tc 1.007 0 0 1.007 551.058 383.934 cm q /FormType 1 >> 0 5.203 TD /FormType 1 /Meta245 259 0 R 0 g /F1 12.131 Tf ET 32.201 5.203 TD Q >> stream /Length 69 /ProcSet[/PDF/Text] /Matrix [1 0 0 1 0 0] /I0 51 0 R 1 i /Matrix [1 0 0 1 0 0] stream Q >> /Resources<< /FormType 1 >> Q Q /Font << /ProcSet[/PDF/Text] endstream /Meta340 354 0 R 0 G /BBox [0 0 88.214 16.44] 292 0 obj q Q /Matrix [1 0 0 1 0 0] 1 i /ProcSet[/PDF] 1 i BT 1.007 0 0 1.007 551.058 277.035 cm Q /FormType 1 0.51 Tc 1 i endstream q endobj Q /F3 17 0 R endobj Q q /ProcSet[/PDF/Text] >> >> /Matrix [1 0 0 1 0 0] 261 0 obj Q /Resources<< q 1.014 0 0 1.007 531.485 330.484 cm ET 0 G q q endobj >> /Meta142 156 0 R /Font << >> << /ProcSet[/PDF] /Type /XObject /Length 64 Q /Subtype /Form q >> /Meta398 Do Q Decreased by another number means subtract. So let's go ahead and identify a v /BBox [0 0 534.67 16.44] >> /Type /XObject 1 i /Subtype /Form ET /ProcSet[/PDF/Text] 0 g /Resources<< /F3 12.131 Tf /Resources<< Q /FormType 1 /BBox [0 0 534.67 16.44] 0 g Q Q q BT endstream /Font << 1 i 1 g >> q >> 0 w /Matrix [1 0 0 1 0 0] /Type /XObject 672.261 726.464 m /FormType 1 q q /Meta1 Do Q /ProcSet[/PDF] /BBox [0 0 15.59 16.44] 92 0 obj /FormType 1 q /F3 12.131 Tf ET 0 G 0.564 G >> /BBox [0 0 30.642 16.44] ET q /Meta119 Do /Meta95 109 0 R 0.786 Tc 1.007 0 0 1.007 551.058 330.484 cm 0.737 w (x) Tj endobj 316 0 obj 1.007 0 0 1.006 411.035 510.406 cm endobj endobj q /Meta4 13 0 R ET /FormType 1 stream 1.014 0 0 1.007 531.485 636.879 cm (A\)) Tj (11) Tj /Resources<< stream